2^(x-1)*4^(x+1)/8^(x-1)=64

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Solution for 2^(x-1)*4^(x+1)/8^(x-1)=64 equation: 



2^(x-1)*4^(x+1)/8^(x-1)=64

We move all terms to the left:

2^(x-1)*4^(x+1)/8^(x-1)-(64)=0



Domain of the equation: 8^(x-1)!=0

x∈R



We multiply all the terms by the denominator


2^(x-1)*4^(x+1)-64*8^(x-1)=0

Wy multiply elements

2^(x-1)*4^(x+1)-512x(x=0

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